Question

A bus started from rest and moved with uniform acceleration. It acquired a speed of 60 m/s after 100 seconds. What is the acceleration and the distance traveled after 100 seconds?

Answer 1

We can find the acceleration of the bus from the kinematic equation:

$$v=v_0+at,$$ $$a=\dfrac{v-v_0}{t}=\dfrac{60\ \dfrac{m}{s}-0\ \dfrac{m}{s}}{100\ s}=0.6\ \dfrac{m}{s^2}.$$

We can find the distance traveled after 100 seconds from another kinematic equation:

$$d=v_0t+\dfrac{1}{2}at^2,$$ $$d=0\ \dfrac{m}{s}\cdot 100\ s+\dfrac{1}{2}\cdot 0.6\ \dfrac{m}{s^2}\cdot (100\ s)^2=3000\ m.$$

Answer:

$a=0.6\ \dfrac{m}{s^2}.$

$d=3000\ m.$