a given mass of chlorine occupies 38cm2 at 20°c. Determine it final volume at 45°c. Pressure remains constant
For isobaric process (constant pressure), V1T1=V2T2\frac{V_1}{T_1} = \frac{V_2}{T_2}T1V1=T2V2, where the temperature is in kelvins. Hence, V2=V1T2T1=38cm3⋅293.15K318.15K=35.01cm3V_2 = \frac{V_1 T_2}{T_1} = \frac{38 cm^3 \cdot 293.15 K}{318.15K} = 35.01 cm^3V2=T1V1T2=318.15K38cm3⋅293.15K=35.01cm3
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