Question

a train started from rest and accelerated uniformly to 12m/s in 6s.this velocity is maintained for 1 minutes .after that the train is decelerated uniformly until it stopped for the next 24s.Draw a v-t graph for the motion and find the total distace travelled

Answer 1

The distance traveled is the area below the red graph:

$$d=\frac12\cdot6\cdot12+(66-6)\cdot12+\frac12\cdot24\cdot12=900\text{ m}.$$