Question #141694
1. a) A fidget spinner is rotating at a certain angular velocity. As it began to slow down, it
took 45 seconds to stop with an average angular acceleration of 0.69 rads-2
. Calculate
the
(i) initial angular velocity in rpm.
(ii) number of revolution the spinner makes before it stops.
1
Expert's answer
2020-11-02T09:23:06-0500

The angular acceleration is


α=ω2ω1t, ω2=αt+ω1=0.6945+0=45.69 rad/s.\alpha=\frac{\omega_2-\omega_1}{t},\\\space\\ \omega_2=\alpha t+\omega_1=0.69\cdot45+0=45.69\text{ rad/s}.

The number of revolutions before it stopped is


n=ω22π=45.692π=7.272.n=\frac{\omega_2}{2\pi}=\frac{45.69}{2\pi}=7.272.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS