Question #141375
A stone thrown horizontal from the top of vertical wall with a velocity of 15m/s^1 hit the horizontal ground at a point 45m from the base of the wall. Calculate time of flight of the Stone
1
Expert's answer
2020-10-30T13:18:11-0400

The horizontal component of the velocity (vx=15m/sv_x = 15m/s ) does not change during the falling. Thus, if the stone covered the distance d=45md = 45m during the falling, then it would take the following time:


t=dvx=45m15m/s=3st =\dfrac{d}{v_x} = \dfrac{45m}{15m/s} = 3s

Answer. 3s.


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