According to the following figure:
The coordinates of the vectors will be:
"\\mathbf{v}_1 = (-25,0)\\space m\\\\\n\\mathbf{v}_2 = (61\\cos30\\degree ,61\\sin30\\degree) = (30.5\\sqrt2 ,30.5)\\space m\\\\\n\\mathbf{v}_3 = (92\\cos49.4\\degree ,-92\\sin49.4\\degree) \\approx (59.87 ,-69.85)\\space m\\\\" The resultant vector:
"\\mathbf{x} = \\mathbf{v}_1 + \\mathbf{v}_2 + \\mathbf{v}_3=\\\\\n=(-25+30.5\\sqrt2 + 59.87, 0+30.5-69.85) \\approx (78,-39.35)\\space m" Answer. "\\mathbf{x} = (78,-39.35)\\space m".
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Your answer is excellence, very helpful for me. Thank you very much...
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