In space, a 5.82×10^6kg rocket experiences a constant force of 6.94×10^9N in the direction of its movement. At time t=0s, it flies past a planet at a velocity of 57.2m/s. How far away is the rocket from the planet when t=25.4s?
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Expert's answer
2020-10-27T08:25:07-0400
The acceleration of the rocket can be found from the Newton's second law:
"a = \\dfrac{F}{m}"
where "F = 6.94\\times 10^9N" and "m = 5.82\\times 10^6kg". Then the distance covered by the rocket is:
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