Question #139979
A fighter jet is catapulted off an aircraft carrier from rest to 75 m/s. If the aircraft carrier deck is 100 m long, what is the acceleration of the jet?
1
Expert's answer
2020-10-23T11:50:56-0400

We can find the acceleration of the fighter jet from the kinematic equation:


v2=v02+2as,v^2=v_0^2+2as,

here, v0=0 msv_0=0\ \dfrac{m}{s} is initial velocity of the fighter jet, v=75 msv=75\ \dfrac{m}{s} is the final velocity of the fighter jet, aa is the acceleration of the fighter jet and s=100 ms=100\ m is the length of the aircraft carrier deck.

Then, from this equation we can find the acceleration of the fighter jet:


a=v22s=(75 ms)22100 m=28.1 ms2.a=\dfrac{v^2}{2s}=\dfrac{(75\ \dfrac{m}{s})^2}{2\cdot 100\ m}=28.1\ \dfrac{m}{s^2}.

Answer:

a=28.1 ms2.a=28.1\ \dfrac{m}{s^2}.  


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