Question

the car initially at rest undergoes uniform acceleration for 6.32 seconds and covers a distance of 120 m what is approximate acceleration of the car

Answer 1

We can find the acceleration of the car from the kinematic equation:

$$s=v_0t+\dfrac{1}{2}at^2,$$

here, $s=120\ m$ is the distance traveled by the car, $v_0=0\ \dfrac{m}{s}$ is the inital velocity of the car, $a$ is the acceleration of the car and $t=6.32\ s$ is the time during which the car accelerates.

Then, from this equation we can find the acceleration of the car:

$$a=\dfrac{2s}{t^2}=\dfrac{2\cdot 120\ m}{(6.32\ s)^2}=6.0\ \dfrac{m}{s^2}.$$

Answer:

$a=6.0\ \dfrac{m}{s^2}.$