Question #138286

Compare the annual variation in noon sun angle at 55° N to that at 15°N.

Expert's answer

In the northern hemisphere, on the 22nd of June, the sun rays are perpendicular to the surface of Earth at 23.5°N.

Noon sun angle at 55° N:


θ1s=90−∣55−23.5∣=58.5°,θ2s=90−∣15−23.5∣=81.5°.\theta_{1s}=90-|55-23.5|=58.5°,\\ \theta_{2s}=90-|15-23.5|=81.5°.


Now consider the winter time, December 22, the sun rays are perpendicular to the earth surface at 23.5°S, or "-23.5°N":


θ1w=90−∣55−(−23.5)∣=11.5°,θ2w=90−∣15−(−23.5)∣=51.5°.\theta_{1w}=90-|55-(-23.5)|=11.5°,\\ \theta_{2w}=90-|15-(-23.5)|=51.5°.


The annual variations are


Δθ1=θ1s−θ1w=47°,Δθ2=θ2s−θ2w=30°.\Delta\theta_1=\theta_{1s}-\theta_{1w}=47°,\\ \Delta\theta_2=\theta_{2s}-\theta_{2w}=30°.
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