Question #138286
Compare the annual variation in noon sun angle at 55° N to that at 15°N.
1
Expert's answer
2020-10-15T10:45:47-0400

In the northern hemisphere, on the 22nd of June, the sun rays are perpendicular to the surface of Earth at 23.5°N.

Noon sun angle at 55° N:


θ1s=905523.5=58.5°,θ2s=901523.5=81.5°.\theta_{1s}=90-|55-23.5|=58.5°,\\ \theta_{2s}=90-|15-23.5|=81.5°.


Now consider the winter time, December 22, the sun rays are perpendicular to the earth surface at 23.5°S, or "-23.5°N":


θ1w=9055(23.5)=11.5°,θ2w=9015(23.5)=51.5°.\theta_{1w}=90-|55-(-23.5)|=11.5°,\\ \theta_{2w}=90-|15-(-23.5)|=51.5°.


The annual variations are


Δθ1=θ1sθ1w=47°,Δθ2=θ2sθ2w=30°.\Delta\theta_1=\theta_{1s}-\theta_{1w}=47°,\\ \Delta\theta_2=\theta_{2s}-\theta_{2w}=30°.

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