Answer to Question #138241 in Physics for N/a

Question #138241

A cheetah is walking at 1.0m/s when it sees a zebra 25m away. What acceleration would be required to reach 20.0m/s in that distance?

Expert's answer

The required acceleration is

"a=\\frac{v_f^2-v_i^2}{2d}=\\frac{20^2-1^2}{2\\cdot25}=7.98\\text{ m\/s}^2."

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