Question #123928

A body of mass 20 kg moving with a velocity of 10 m/s , is suddenly hit by another body moving in the same direction. If the velocity of the former is changed to 15 m/s, what is the impulse by the first body

Expert's answer

I=Δp=m(v2v1)I=\Delta p=m(v_2-v_1)

I=20(1510)=100 NsI=20(15-10)=100\ Ns


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