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Question #123928
A body of mass 20 kg moving with a velocity of 10 m/s , is suddenly hit by another body moving in the same direction. If the velocity of the former is changed to 15 m/s, what is the impulse by the first body
Expert's answer
I
=
Δ
p
=
m
(
v
2
−
v
1
)
I=\Delta p=m(v_2-v_1)
I
=
Δ
p
=
m
(
v
2
−
v
1
)
I
=
20
(
15
−
10
)
=
100
N
s
I=20(15-10)=100\ Ns
I
=
20
(
15
−
10
)
=
100
N
s
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