Question #120973

The asteroid 101955 Bennu is currently being explored by NASAs OSIRIS-REX mission. bunnu has a mass of 6.24*10^10 kg and a radius of 282 m. A probe on the surface of bennu moves by making small hops of the surface. if the probe hops directly upwards with an initial velocity of 0.0453 m/s, it will reach a maximum height of ..... m before coming back down

Expert's answer

To solve this problem, compute the acceleration due to gravity for this asteroid from the equilibrium between the force of gravity and the universal force of gravity:


mg=GMmR2, g=GMR2.mg=G\frac{Mm}{R^2},\\\space\\ g=\frac{GM}{R^2}.

The height that the hopper will reach can be found from energy conservation principle: the hopper's kinetic energy (assuming no losses) fully turns into potential energy:


mv22=mgh,h=v22g=(vR)22GM, h=(0.0453282)226.67310116.241010=19.6 m.\frac{mv^2}{2}=mgh,\\ h=\frac{v^2}{2g}=\frac{(vR)^2}{2GM},\\\space\\h=\frac{(0.0453\cdot282)^2}{2\cdot6.673\cdot10^{-11}\cdot6.24\cdot10^{10}}=19.6\text{ m}.

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