Question

A copper calorimeter of mass 120g contains 70g of ice at 0degree c. What mass of steam at 100degree c must be passed into the calorimeter to raise a temperature to 40 degree c.

Answer 1

Heat gained by the copper:

$$q_1=m_cC_cΔT = (120) (0.40 ) (40 − 0) = 1920\ J$$

Heat gained by the water:

$$q_2=m_wC_wΔT = (70) (4.2 ) (40 − 0) = 11760\ J$$

Heat gained by the ice:

$$q_3 = m_iL + m_iC_wΔT \\ = (10) (320 ) + (10 ) (4.2 ) (40-0 ) = 4880\ J$$

Heat lost by the steam:

$$q _4= mL_s + mC_wΔT \\= m (2200) + m (4.2 ) (100 − 40) = 2452 m$$

$$1920 + 11760 + 4880 = 2452 m$$

$$m = 7.6\ g$$