Question #118072
a copper plate 3mm thick has a cross sectional area 0.5. one face is at 80 degrees. while the other is 250 degrees. determine the rate of heat transfer through the plate. K=400
1
Expert's answer
2020-05-25T11:05:17-0400
q=kAΔTΔxq=kA\frac{\Delta T}{\Delta x}

q=(400)(0.5)250800.003=1.1107 Wq=(400)(0.5)\frac{250-80}{0.003}=1.1\cdot10^7\ W


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS