Answer to Question #101779 in Physics for Ceaser daniel

Question

The eye of a hurricane passes over Grand Bahama Island in a direction 60.0◦ north of west with a speed of 41.0 km/h. Three hours later the course of the hurricane suddenly shifts due north, and its speed slows to 25.0 km/h. How far from Grand Bahama is the hurricane 4.50 h after it passes over the island?
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Answer 1

$$\bold{d_1}=(41\cos{60}(3),41\sin{60}(3))\ km$$

$$\bold{d_2}=(0,25(1.5))\ km$$

$$\bold{d}=(41\cos{60}(3),41\sin{60}(3)+25(1.5))\ km$$

$$\bold{d}=(61.5,144)\ km$$

$$d=\sqrt{61.5^2+144^2}=157\ km$$