Answer to Question #101727 in Physics for Rosie
2020-01-24T05:34:55-05:00
A kayaker is traveling down a river at 7.5 knots due south when it encounters a current that is 4.3 knots at 43° east of north what is the new speed and direction of the boat
1
2020-01-27T09:30:29-0500
"\\bold{v}=(0,7.5)knots"
"\\bold{u}=(4.3\\sin{43},-4.3\\cos{43})knots"
"\\bold{v'={v+u}}=(4.3\\sin{43},7.5-4.3\\cos{43})=(2.93,4.36)knots"
"v=\\sqrt{2.93^2+4.36^2}=5.3\\ knots" The direction:
"\\theta=\\arctan{\\frac{2.93}{4.36}}=34\\degree\\ east\\ of \\ south"
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