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Light with wavelength 648 nm in air is incident perpendicularly from air on a firm 8.76 nm thick and with refractive index 1.35. Part of the light is reflected from the first surface of the film, and part enters the film and is reflected back at the second surface, where the film is again in contact with air.

(a) How many waves are contained along the path of this second part of the light in its round trip through the film?

(b) What is the phase difference between these two parts of the light as they leave the film?
how is light produce in sky?
unkown spherical mirror is used to form an erect image three times the original size for an object placed at distance 15cm from it find
1-the image position
2-the focal length
3-the kind of the mirror
a light ray initialy in water enters a transprent substance at an angle of inicidence of 37degree and the transmitted ray is refracted at an angle of 25degree calculate the speed of light in the transparent subtance
in young's double slit expmnt. the ratio of max. and min. intensities of fringes are 4:1.what are the amplitudes of the coherent sources?

please answer................
unkown spherical mirror is used to form an erect image three times the original size for an object placed at distance 15cm from it find
1-the image position
2-the focal length
3-the kind of the mirror
can a virtual image be photographed by a camera?
A certain camera has f-numbers that range from 1.3 to 5. If the focal length of the lens is 49 mm, what is the range of aperture diameters for the camera?

Dmin =______ mm

Dmax = _____ mm
Diameter of a plano–convex lens is 6 cm. and its thickness at the centre is 3 mm. What is the focal length of the lens. If the speed of light in the material of lens is 2 × 108 m/s :-
(1) 30 cm
(2) 20 cm
(3) 10 cm
(4) 40 cm
A concave mirror of focal length 'f1' is placed at a distance of 'd' from a convex lens of focal length 'f2'. A beam of light coming from infinity and falling on this convex lens-concave mirror combination returns to infinity. The distance 'd' must equal :
(1) 2f1 + f2
(2) –2f1 + f2
(3) f1 + f2
(4) –f1 + f2
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