Question #42273

Diameter of a plano–convex lens is 6 cm. and its thickness at the centre is 3 mm. What is the focal length of the lens. If the speed of light in the material of lens is 2 × 108 m/s :-
(1) 30 cm
(2) 20 cm
(3) 10 cm
(4) 40 cm

Expert's answer

Answer on Question #42273-Physics-Optics

Diameter of a plane-convex lens is 6cm6\mathrm{cm} . and its thickness at the center is 3mm3\mathrm{mm} . What is the focal length of the lens? If the speed of light in the material of lens is 2×108 m/s2\times 108~\mathrm{m / s} :-

(1) 30cm30\mathrm{cm} (2) 20cm20\mathrm{cm} (3) 10cm10\mathrm{cm} (4) 40cm40\mathrm{cm}

Solution

v=2108ms,c=3108ms,μ=cv=1.5,D=6cm=60mm,R=D2=30mm.v = 2\cdot 10^{8}\frac{m}{s},c = 3\cdot 10^{8}\frac{m}{s},\mu = \frac{c}{v} = 1.5,D = 6cm = 60mm,R = \frac{D}{2} = 30mm.

Here we have to find the radius of the surface of the lens. OO is the center of the circle. So AC is the chord of the circle. By Pythagoras's theorem


R2=302+(R3)2R2=900+R26R+9R=15cm.R ^ {2} = 3 0 ^ {2} + (R - 3) ^ {2} \rightarrow R ^ {2} = 9 0 0 + R ^ {2} - 6 R + 9 \rightarrow R = 1 5 c m.


By lens makers formula for a plane-convex lens


1f=(μ1)1Rf=R(μ1)=15cm1.51=30cm.\frac {1}{f} = (\mu - 1) \cdot \frac {1}{R} \rightarrow f = \frac {R}{(\mu - 1)} = \frac {1 5 c m}{1 . 5 - 1} = 3 0 c m.


Answer: 30 cm30~\mathrm{cm}

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