Question #38958

A parallel beam of monochromatic light falls on a combination of a convex lens and a concave lens of focal lengths 15 cm and 5 cm respectively.What is the distance between the two lenses to obtain a parallel beam of light from the concave lens?
options are :
a) 20 cm b) 3 cm c) 10 cm d) 45 cm
1

Expert's answer

2014-02-10T04:53:41-0500

Answer on Question 38958, Physics, Optics We will use formula for 2-lens system here. The effective focal length of such system is

1feff=1f1+1f2lf1f2\frac{1}{f_{eff}}=\frac{1}{f_{1}}+\frac{1}{f_{2}}-\frac{l}{f_{1}f_{2}}

feff=11f1+1f2lf1f2f_{eff}=\frac{1}{\frac{1}{f_{1}}+\frac{1}{f_{2}}-\frac{l}{f_{1}f_{2}}}

where f1f_{1}, f2f_{2} are focal lengthes of the 1 and lens and ll is distance between them. For concave lens f2f_{2} should be negative.

We need fefff_{eff} to be infinity if we want to keep parallel beam parallel. Hence, equation for distance ll is

1f1+1f2lf1f2=0\frac{1}{f_{1}}+\frac{1}{f_{2}}-\frac{l}{f_{1}f_{2}}=0

l=(1f1+1f2)f1f2l=\left(\frac{1}{f_{1}}+\frac{1}{f_{2}}\right)f_{1}f_{2}

l=(11515)155=10cml=-\left(\frac{1}{15}-\frac{1}{5}\right)\cdot 15\cdot 5=10\,cm

Hence, answer is c) 10 cm.


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