Answer on Question 38958, Physics, Optics We will use formula for 2-lens system here. The effective focal length of such system is
feff1=f11+f21−f1f2l
feff=f11+f21−f1f2l1
where f1, f2 are focal lengthes of the 1 and lens and l is distance between them. For concave lens f2 should be negative.
We need feff to be infinity if we want to keep parallel beam parallel. Hence, equation for distance l is
f11+f21−f1f2l=0
l=(f11+f21)f1f2
l=−(151−51)⋅15⋅5=10cm
Hence, answer is c) 10 cm.
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