Question #38953

A small object is placed 20 cm in front of a block of glass 10 cm thick and its farther side silvered.The image is formed 22 cm behind the silvered face.Find refractive index of glass.
options are :
(1) 1.15
(2) 1.25
(3) 1.67
(4) 1.1
1

Expert's answer

2014-02-10T09:43:05-0500

Answer on Question #38953, Physics, Optics

A small object is placed 20 cm in front of a block of glass 10 cm thick and its farther side silvered. The image is formed 22 cm behind the silvered face. Find refractive index of glass.

options are :

(1) 1.15

(2) 1.25

(3) 1.67

(4) 1.1

Solution:

Refractive index n = Real depth/Apparent depth.

Thus,


n=20xn = \frac{20}{x}


Silvered surface act as mirror.

Thus, to get the image 22 cm behind, the object should be 22 cm in front.

x + thickness of glass = 22


x+10=22x=2210=12\begin{array}{l} x + 10 = 22 \\ x = 22 - 10 = 12 \end{array}


Thus


n=2012=1.67n = \frac{20}{12} = 1.67

Answer. (3) 1.67.

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Comments

Assignment Expert
02.07.18, 16:20

Dear Muskan, this problem can be solved in a following way. Observer will see the mirror closer due to refraction in glass slab. Let now consider this distance as 20 + x. On the other hand, image distance from the mirror should be the same and we can write as 22 + (10 - x). Now we can find that x = 6, and the real depth of the slab is 10. So we obtain the same answer n=10/6=1.67

Muskan
29.06.18, 08:30

Why we have add x to the thickness of glass slab and equate it to 22

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