Answer on Question #38953, Physics, Optics
A small object is placed 20 cm in front of a block of glass 10 cm thick and its farther side silvered. The image is formed 22 cm behind the silvered face. Find refractive index of glass.
options are :
(1) 1.15
(2) 1.25
(3) 1.67
(4) 1.1
Solution:
Refractive index n = Real depth/Apparent depth.
Thus,
Silvered surface act as mirror.
Thus, to get the image 22 cm behind, the object should be 22 cm in front.
x + thickness of glass = 22
Thus
Answer. (3) 1.67.
Comments
Dear Muskan, this problem can be solved in a following way. Observer will see the mirror closer due to refraction in glass slab. Let now consider this distance as 20 + x. On the other hand, image distance from the mirror should be the same and we can write as 22 + (10 - x). Now we can find that x = 6, and the real depth of the slab is 10. So we obtain the same answer n=10/6=1.67
Why we have add x to the thickness of glass slab and equate it to 22