Answer to Question #317036 in Optics for naji

Question #317036

Amultimodestep-indexfiberhascoreand cladding refractive indices of 1,475 and 1.458 respectively. If it has a core radius of 30 μm and operates at a wavelength of 1250 nm.



– What should be the core radius of the fiber if it is to operate as a single mode fiber

1
Expert's answer
2022-03-24T16:36:50-0400

Now we know that

N.A=n12n22\sqrt{n_1^2-n_2^2}


NA=1.47521.4582=0.2232NA=\sqrt{1.475^2-1.458^2}=0.2232

λc=2πa(NA)Vmax\lambda_c=\frac{2\pi a(NA)}{V_{max}}

a=λcVmax2π(NA)a=\frac{\lambda_c V_{max}}{2\pi (NA)}

a=1250×109×2.4052×3.14×0.2232a=\frac{1250\times10^{-9}\times2.405 }{2\times3.14 \times0.2232}

a=2.14×106ma=2.14\times10^{-6}m


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