Question #314882

A 14.5 cm high object is placed 50.0 cm in front of a concave mirror with radius of curvature equal to 30.0 cm. determine the distance, height, and image formed by the mirror.

1
Expert's answer
2022-03-21T12:45:27-0400

Answer

The height of the object is ho = 14.5 cm

The object is placed in front of the mirror at a distance of u = 50 cm

The radius of the curvature of the mirror is R = 30 cm

 Now,

From the sign convention, the object distance is u = -50 cm

From the sign convention, the radius of curvature is R = -30 cm


The expression for the mirror formula is

1f=1u+1v\frac{1}{f}=\frac{1}{u}+\frac{1}{v}


Putting all values

v=-21.42cm


Height of image

hi=h0vu=(21.4214)50=6.21cmh_i=-\frac{h_0v}{u}\\=-\frac{(-21.42*14)}{-50}\\=-6.21cm


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