Answer to Question #314882 in Optics for Mark

Question

A 14.5 cm high object is placed 50.0 cm in front of a concave mirror with radius of curvature equal to 30.0 cm. determine the distance, height, and image formed by the mirror.

Answer 1

Answer

The height of the object is h_o = 14.5 cm

The object is placed in front of the mirror at a distance of u = 50 cm

The radius of the curvature of the mirror is R = 30 cm

 Now,

From the sign convention, the object distance is u = -50 cm

From the sign convention, the radius of curvature is R = -30 cm

The expression for the mirror formula is

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

Putting all values

v=-21.42cm

Height of image

$h_i=-\frac{h_0v}{u}\\=-\frac{(-21.42*14)}{-50}\\=-6.21cm$