Question

A 8.6 cm tall object is placed at 37cm from convex lens with a focal length of 10cm . • where will the image be located ? • how big will the image be and what will the orientation be ? • A prescription for a corrective lens is 4.0 diopters. The lens maker uses a glass with an index of refraction of 1.54. If the radius of curvature of the front surface of the lens is 32 centimeters, what must the radius of curvature be for the other surface of the lens ??

Answer 1

1)

$\frac 1F=\frac 1f+\frac 1d,$

$f=\frac{dF}{d-F}=13.7~cm,$

$\Gamma=\frac fd=\frac Hh,$

$H=h\frac fd=3.2~cm,$

an inverted real image behind a lens.

2)

$D=(n-1)(\frac 1{R_1}+\frac 1{R_2}),$

$R_2=\frac{R_1(n-1)}{DR_1-n+1}=0.136~cm.$