Answer to Question #187656 in Optics for Anas

Question #187656

Convex lens is illuminated by a plane wave which is propagating along z-axis. Sketch and nd out

mathematical expressions of wavefronts within each part of the optical system. Focus of both lenses are

f. The pattern t(x; y) is given as 1/2*[1+ cos(2x=10)]


1
Expert's answer
2021-05-04T06:10:55-0400

Given data:

Pattern t(x,y)=12[1+cos(2πx/10)]t(x,y)=\dfrac{1}{2}[1+cos(2\pi x/10)]

=12[2cos2(πx10)]=cos2(πx/10)= \frac{1}{2}[2cos^2(\frac{\pi x}{10})]=cos^2(\pi x/10)


(a) Wave front behavior at f

uˉ=f\bar u =-f [wave focus on focal point means intense wave form arises at focal point]

1v1(f)=1f1v=0v=\dfrac{1}{v}-\dfrac{1}{(-f)}=\dfrac{1}{f}\\\Rightarrow \dfrac{1}{v}=0\\\Rightarrow v= \infty


Image at infinity but density is squared



(b) Wave front behavior at 2f

[On 2f position wave normalize the wave front ]


uˉ=2f1v=1u+1f=1(3f)+1f=23fSo Size=(32)times\bar u =-2f\\\dfrac{1}{v}=\dfrac{1}{u}+\dfrac{1}{f}=\dfrac{1}{(-3f)}+\dfrac{1}{f}=\dfrac{2}{3f}\\\Rightarrow So\ Size = (\dfrac{3}{2})times


As the wave front is squared , So it is always it the positive direction




vu=32\dfrac{-v}{u}=\dfrac{3}{2} [At 2f] ; vu=\dfrac{-v}{u}=\infty [At f]

(Magnification here infinity represent the order of t(x,y) is vary much less than order at f)


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