Question #162579

A 750nm light beam in air hits the flat surface of a certain liquid, and the beam is split into a reflected ray and a refracted ray. If the reflected ray is completely polarized when it is at 36.0 degrees with respect to the surface, what is the wavelength of the refracted ray?


Expert's answer

With a grazing angle of 36.036.0^∘ (measured from the surface), the angle of incidence is 54.054.0^∘ , which equals the polarizing angle:

tanθp=n2n1=n1.00=n=tan54.0o=1.38tan\theta_p = \frac{n_2}{n_1} = \frac{n}{1.00} = n = tan54.0^o = 1.38

In the liquid, λn=λn=750nm1.38=545nm\lambda_n = \frac{\lambda}{n} = \frac{750nm}{1.38} = 545nm


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