Solution
We are applying momentim conservation
m1u1+m2u2=m1v1+m2v2m_1u_1+m_2u_2=m_1v_1+m_2v_2m1u1+m2u2=m1v1+m2v2
Where
u1and u2 are initial velocity
And v1 and v2 are final velocity.
Using all data in question
5×15−8×4=−5×4+8×v2v2=7.8m/s5\times15-8\times4=-5\times4+8\times v_2\\v_2=7.8m/s5×15−8×4=−5×4+8×v2v2=7.8m/s
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