the Van der Waals equation:
"(p+\\frac{a\\nu^2}{V^2})(V-b\\nu)=\\nu RT\\\\\nV^3-(\\frac{RT}{p}+b)\\nu V^2+\\frac{a\\nu^2}{p}V-\\frac{ab\\nu^3}{p}=0\\\\\nV^3-5.9172V^2+0.000422V-7.2162\\cdot10^{-6}=0"
If we solve that equation, then we get "V=5.92713 \\, L"
Comments
Leave a comment