Question

a bubble of 5.0 mol of helium is submerged at a certain depth in liquid water when the water undergoes a temperature increase VT of 20 centigrade at constant pressure .As a result the bubble expands.How much heat Q is added to the helium during the expansion and temperature increase?

Answer 1

The temperature increase:

$$\Delta T=20\ K$$

$$Q=\frac{5}{2}nR\Delta T$$

$$Q=\frac{5}{2}(5.0)(8.31)(20)=2100\ J=2.1\ kJ$$