We assume, that mass of the wooden box without 100 kg box << "m=100\\, kg" box. Then the horizontal force needed to start the crate moving is
"F=\\mu mg,"where "\\mu" is the coefficient of static friction between the wood and the surface on which the crate rests.
For example, average of static friction between wood and metal is "\\mu_{w,m}=0.4" [1]. So, with "g=9.8 \\, m\/s^2" we have
"F=0.4\\cdot 100 \\cdot 9.8=392\\, N."[1] http://www.engineershandbook.com/Tables/frictioncoefficients.htm
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