Question #88448
Two children stretch a jump rope between them and send wave pulses back and forth on it. The rope is 2.7 m long, its mass is 0.46 kg, and the force exerted on it by the children is 37 N.

(a)
What is the linear mass density of the rope (in kg/m)?



(b)
What is the speed of the waves on the rope (in m/s)?
1
Expert's answer
2019-04-24T09:49:11-0400

(a) The linear mass density ρ of the rope is its mass m per unit of length:

ρ=mL\rho =\frac{m}{L}

Substituting m=0.46 kg and L=2.7 m we get

ρ=0.46kg2.7m0.17kgm\rho =\frac{0.46\,kg}{2.7\,m}\approx 0.17\frac{kg}{m}

So the linear mass density of the rope is 0.17 kg/m

(b) If the tension in the rope is T, and the linear density is ρ, then the speed of the waves u on the rope is determined by

u=Tρu=\sqrt{\frac{T}{\rho }}

Substituting T=37 N and ρ=0.17 kg/m we get

u=37N0.17kgm=37kgms20.17kgm14.8msu=\sqrt{\frac{37\,N}{0.17\,\frac{kg}{m}}}=\sqrt{\frac{37\,kg\cdot \frac{m}{{{s}^{2}}}\,}{0.17\frac{kg}{m}\,}}\approx 14.8\,\frac{m}{s}

So the speed of the waves on the rope is 14.8 m/s


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