Question #8520

The temperature at which the tungsten filament of a 12V and 36W lamp operates is 1730 Degrees Celsius. If the temperature coefficient of resistance of tungsten is 610^−3/K, find the resistance of the lamp at a room temperature of 20 Degrees Celsius.

(A) 10.00 ohms

(B) 0.45 ohms

(C) 0.39 ohms

(D) 4.00 ohms

Expert's answer

Question#8520

The temperature at which the tungsten filament of a 12V and 36W lamp operates is 1730 Degrees Celsius. If the temperature coefficient of resistance of tungsten is 610C/K610{}^{\circ} \mathrm{C} / \mathrm{K}, find the resistance of the lamp at a room temperature of 20 Degrees Celsius.

(A) 10.00 ohms

(B) 0.45 ohms

(C) 0.39 ohms

(D) 4.00 ohms

Solution:

Let:


U=12V, P=36W, T1=1730C, T2=20C, α=6103 K1U = 12V, \ P = 36W, \ T1 = 1730{}^{\circ}C, \ T2 = 20{}^{\circ}C, \ \alpha = 6 \cdot 10^{-3} \ \mathrm{K}^{-1}R2=?R2 = ?


Find resistance of a lamp at 1730C1730{}^{\circ}C

P=IU, I=URP = I U, \ I = \frac{U}{R}P=U2RP = \frac{U^2}{R}R=U2PR = \frac{U^2}{P}R1=12236=4 ohmsR1 = \frac{12^2}{36} = 4 \ \mathrm{ohms}


Dependence of resistance on temperature is:


R1=R2(1+αΔT)=>R1 = R2(1 + \alpha \Delta T) =>R2=R11+αΔTR2 = \frac{R1}{1 + \alpha \Delta T}ΔT=T1T2=1710C\Delta T = T1 - T2 = 1710{}^{\circ}CR2=41+61031710=0.36 ohmsR2 = \frac{4}{1 + 6 \cdot 10^{-3} \cdot 1710} = 0.36 \ \mathrm{ohms}


Answer: "C" (nearest value) Resistance is: 0.36 ohms

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