Question #84470

For an intrinsic semiconductor with a band gap of 0.75eV, calculate the effective density of states for the electrons and the concentration of electrons in the conduction band at T=300K, given that the effective masses of the electron and hole are equal to the free mass of the electron.

Expert's answer

The effective density of states for the electron in the conduction band (take

me=m0m_e^*=m_0

):

NC=2[2πmekTh2]3/2=N_C=2[\frac{2\pi m_e^*kT}{h^2}]^{3/2}==2[2π9.1110311.381023300(6.631034)2]3/2=2.51025 m3.=2[\frac{2\pi\cdot 9.11\cdot 10^{-31}\cdot 1.38\cdot 10^{-23}\cdot 300}{(6.63\cdot 10^{-34})^2}]^{3/2}=2.5\cdot 10^{25} \text{ m}^{-3}.

The same will be for the valence band according to the condition:

NV=2[2πmhkTh2]3/2=NC=2.51025 m3.N_V=2[\frac{2\pi m_h^*kT}{h^2}]^{3/2}=N_C=2.5\cdot 10^{25} \text{ m}^{-3}.

The concentration of electrons in the conduction band:

ni=NCNVeEg/2kT=n_i=\sqrt{N_C N_V}\cdot e^{-E_g/2kT}==2.51025exp(0.751.61019/(21.381023300))==2.5\cdot 10^{25}\cdot \text{exp}(-0.75\cdot 1.6\cdot 10^{-19}/(2\cdot 1.38\cdot 10^{-23}\cdot 300))==1.251019 m3.=1.25\cdot 10^{19}\text{ m}^{-3}.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS