Question #84469

A square lattice has a side of 3.2 Å. Calculate the momentum and energy of an electron whose wave terminates at the boundary of the first Brillouin zone.

Expert's answer

Answer on Question #84469 - physics - Thermodynamics

1. A square lattice has a side of 3.2 Å. Calculate the momentum and energy of an electron whose wave terminates at the boundary of the first Brillouin zone.

Answer:

Calculate the energy of the free electron by the relation as follows:


E=h2π2ma2E = \frac {h ^ {2} \pi^ {2}}{m a ^ {2}}


Here, hh is the plank constant, mm is the mass of electron and aa is the side of lattice.


E=(6.62×1034)2(3.14)2(9.1×1031)(3.2×1010)2E = \frac {(6.62 \times 10^{-34})^2 (3.14)^2}{(9.1 \times 10^{-31}) (3.2 \times 10^{-10})^2}

E=4.63×1017E = 4.63 \times 10^{-17} joule

Calculate the momentum of electron by the relation as follows:


P=2m(E)P = \sqrt {2 m (E)}P=2(9.1×1031)(4.63×1017)P = \sqrt {2 (9.1 \times 10^{-31}) (4.63 \times 10^{-17})}P=126.4×1048P = \sqrt {126.4 \times 10^{-48}}P=11.24×1024 kgm/sP = 11.24 \times 10^{-24} \ \mathrm{kg \cdot m/s}


Answer:

E=4.63×1017E = 4.63 \times 10^{-17} joule

P=11.24×1024 kgm/sP = 11.24 \times 10^{-24} \ \mathrm{kg \cdot m/s}

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