Question #73275

some cooking pans have a layer of cooper on the bottom.how many kilojoules are needed to raised rhe temperature of 125 degree Celsius to 325 degree celsius

Expert's answer

We have to use the equation to find heat energy:
Q=cm∆T,
where
Q is heat energy;
c is heat capacity (for copper c = 0.39 kJkg-1K-1);
m is a mass of the material, kg
∆T= T_2-T_1=325°C-125°C=220°C=220K
The difference between temperatures in degree Kelvin is the same that in degree Celsius.
Q=kJ/(kg×K)×kg×K=kJ
Q=0.39×m×220=85.8m
To find how many kJ are needed we have to know the mass of the copper layer in kg.
Answer:
Q = 85.8m (kJ)

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