Question

The mean speed of oxygen molecule is 450 m/s. If the radius of an oxygen molecule is 1.8 x 10^-10m, calculate mean time between two successie collisions and mean free path. Take n = 3 x 10^25 m

Answer 1

Answer on Question #62149 – Physics – Molecular Physics – Thermodynamics

Question:

The mean speed of oxygen molecule is $450~\mathrm{m/s}$. If the radius of an oxygen molecule is $1.8 \times 10^{\wedge} - 10\mathrm{m}$, calculate mean time between two successive collisions and mean free path. Take $n = 3 \times 10^{\wedge}25\mathrm{m}$.

Answer:

$$l = \frac{1}{\sqrt{2}\pi d^{2}n} = \frac{1}{4\sqrt{2}\pi r^{2}n} = 5.789 \cdot 10^{-8}~\mathrm{m};$$ $$t = \frac{l}{v} = 1.286 \cdot 10^{-10}~\mathrm{sec};$$

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