Question #60517

a closed vesswl having capacity200ml is filled with hydrogen gas STP. calculate:
number of moles of hydrogen gas filled in the vessel
pressure of hydrogen gas in the vessel ai 273 degree c
root mean square velocity of hydrogen gas at STP
the value of Cp and Cv for hydrogen gas

Expert's answer

Answer on Question #60517, Physics /

a closed vessel having capacity 200ml is filled with hydrogen gas STP.

calculate:

number of moles of hydrogen gas filled in the vessel

pressure of hydrogen gas in the vessel at 273 degree C

root mean square velocity of hydrogen gas at STP

the value of Cp and Cv for hydrogen gas

Find: v?p?u?Cp?Cv?v - ?p - ?u - ?Cp - ?Cv - ?

Given:

V=200×106 m3V = 200 \times 10^{-6} \mathrm{~m}^{3}

M=2×103 kg/m3M = 2 \times 10^{-3} \mathrm{~kg} / \mathrm{m}^{3}

T0=273 KT_0 = 273 \mathrm{~K}

P0=105 PaP_0 = 10^5 \mathrm{~Pa}

R=8,31 J/molR = 8,31 \mathrm{~J} / \mathrm{mol}

T=273+273 K=546 KT = 273 + 273 \mathrm{~K} = 546 \mathrm{~K}

NA=6,02×1023 mol1N_A = 6,02 \times 10^{23} \mathrm{~mol}^{-1}

k=1,38×1023 J/Kk = 1,38 \times 10^{-23} \mathrm{~J} / \mathrm{K}

i=5i = 5

Solution:

Equation of state for ideal gas:


p0V=mMRT0p_0 V = \frac{m}{M} R T_0


Number of moles:


v=mMv = \frac{m}{M}


where M – molar mass

Of (1) and (2) v=p0VRT0\Rightarrow v = \frac{p_0 V}{R T_0}

Of (3) v=8,8×103 mol\Rightarrow v = 8,8 \times 10^{-3} \mathrm{~mol}

Pressure of hydrogen gas:


p=nkTp = n k T


Concentration:


n=NVn = \frac{N}{V}


Number of molecules:

N=vNAN = v N_A

Of (6) N=53×1020\Rightarrow N = 53 \times 10^{20}

Of (5) \Rightarrow n = 0,26 × 10²⁶ 1m3\frac{1}{\mathrm{m}^3} (8)

(7) and (8) in (4): p=200×103p = 200 \times 10^3 Pa

Root mean square velocity:


u=3RT0M(9),u = \sqrt{\frac{3RT_0}{M}} \quad (9),


where T0=273T_0 = 273 K (gas at STP)

Of (9) \Rightarrow u=1840m/su = 1840 \, \text{m/s}

Molar heat of the gas at constant volume:


Cv=i2R(10),C_v = \frac{i}{2} R \quad (10),


where ii – number of degrees of freedom

Of (10) \Rightarrow Cv=20,78J/KC_v = 20,78 \, \text{J/K}

Molar heat of gas at constant pressure:


Cp=i+22R(11)C_p = \frac{i + 2}{2} R \quad (11)


Of (11) \Rightarrow Cp=29,08J/KC_p = 29,08 \, \text{J/K}

**Answer:**

number of moles: u=8,8×103u = 8,8 \times 10^{-3} mol

pressure of hydrogen gas in the vessel at 273 degree C: p=200×103p = 200 \times 10^3 Pa

root mean square velocity of hydrogen gas at STP: u=1840m/su = 1840 \, \text{m/s}

the value of CpC_p and CvC_v for hydrogen gas: Cv=20,78J/KC_v = 20,78 \, \text{J/K}, Cp=29,08J/KC_p = 29,08 \, \text{J/K}

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