Question

1. a vessel contains non linear triatomic gas. if 50% of gas dissociates into individual atom then find the new degree of freedom by ignoring the vibrational mode and further dissociation.(Ans-3.75)

2.A narrow glass tube 80 cm long and opened at both ends is half immersed in mercury and now the top of the tube is closed and is taken out of mercury. A column of mercury 20 cm long remains in the tube. Find atm pressure(ans-60 cm of Hg column)

3.The mean free path of a molecule of He gas is A. Its mean free path along any arbitary cordinate axis will be?(ans-A/3)

4.Two container A and B are partly filled with water and closed. The volume of A is twice of B and it contains half the amount of water in B. IF both are at same temperature the water vapour in the container will have pressure ratio? (ans-1:1)

Answer 1

1. The degree of freedom non linear triatomic gas $i_1 = 6$

The degree of freedom individual atom gas $i_2 = 3$

The result degree of freedom is $0.5 * i_{1} + 0.5 * i_{2} = 0.5 * 9 = 4.5$

2. Use Boyle's law

$$P _ {0} * \frac {H}{2} * S = P _ {1} * (H - h) * S$$ $$P _ {0} * 4 0 = P _ {1} * 6 0$$ $$P _ {1} = P _ {0} * \frac {2}{3}$$

Atmospheric pressure is $P_0 = 760 \, \text{mm}$ of column of mercury

$$P _ {1} = 7 6 0 * \frac {2}{3} = 5 0 6 \text{ mm}$$

3.

Its mean free path along any arbitrary coordinate axis will be A

4. 1:1

http://www.AssignmentExpert.com/