Answer on Question #50679-Physics-Molecular Physics-Thermodynamics
Show that the partition function of an N-particle system is given by the expression:
Zn=ZN=h3NVN(β2πm)23N
Obtain expressions for (i) heat capacity at constant volume, (ii) average pressure exerted by the gas, and (iii) Helmholtz free energy F.
Solution
Let us now practice calculating thermodynamic relations using the partition function by considering an example with which we are already quite familiar: i.e., an ideal monatomic gas. Consider a gas consisting of $N identical monatomic molecules of mass m enclosed in a container of volume V. Let us denote the position and momentum vectors of the i-th molecule by ri and pi, respectively. Since the gas is ideal, there are no interatomic forces, and the total energy is simply the sum of the individual kinetic energies of the molecules:
E=i=1∑N2mpi2.
Let us treat the problem classically. In this approach, we divide up phase-space into cells of equal volume hf. Here, f is the number of degrees of freedom, and h is a small constant with dimensions of angular momentum which parameterizes the precision to which the positions and momenta of molecules are determined. Each cell in phase-space corresponds to a different state. The partition function is the sum of the Boltzmann factor exp(−βEr) over all possible states, where Er is the energy of state r. Classically, we can approximate the summation over cells in phase-space as an integration over all phase-space. Thus,
Z=∫⋯∫exp(−βE)h3Nd3r1…d3rNd3p1…d3pN.
where 3N is the number of degrees of freedom of a monatomic gas containing N molecules. The above expression reduces to
Z=h3NVN∫⋯∫exp(−β2mp12)d3p1…exp(−β2mpN2)d3pN.
Note that the integral over the coordinates of a given molecule simply yields the volume of the container, V, since the energy E is independent of the locations of the molecules in an ideal gas. There are N such integrals, so we obtain the factor VN in the above expression. Note, also, that each of the integrals over the molecular momenta is identical: they differ only by irrelevant dummy variables of integration. It follows that the partition function Z of the gas is made up of the product of N identical factors: i.e.,
Z=ζN,
where
ζ=h3V∫exp(−β2mp2)d3p.
The integral is easily evaluated:
∫exp(−β2mp2)d3p=∫−∞∞exp(−β2mpx2)dpx⋅∫−∞∞exp(−β2mpy2)dpy⋅∫−∞∞exp(−β2mpz2)dpz=(β2πm)23.
Thus,
Z=h3NVN(β2πm)23N.
(i)
CV=(∂T∂Eˉ)V.Eˉ=−∂β∂lnZ=β23N=23NkT.CV=23Nk.
(ii)
pˉ=β1∂V∂lnZ=β1VN=VNkT.
(iii)
F=−kTlnZ=−NkTln(h3V(2πmkT)23).
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