Question #349740

An ideal gas is placed in a 4L container at a temperature of 300K and a pressure of 6

atmospheres. The pressure is held constant while the volume of the gas is halved. What is the

new temperature of the gas?

A. 1200K

B. 600K

C. 300K

D. 150K

E. 75K


Expert's answer

Given:

V1=4 LV_1=4\:\rm L

V2=2 LV_2=2\:\rm L

T1=300 KT_1=300\:\rm K


At the constant pressure the ratio of volume to temperature is constant, so

V1T1=V2T2\frac{V_1}{T_1}=\frac{V_2}{T_2}

Thus, the final temperature

T2=T1V2V1=300∗24=150 KT_2=T_1\frac{V_2}{V_1}=300*\frac{2}{4}=150\:\rm K

Answer: D. 150K


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