Question

Work done by a substance in reversible nonflow manner in accordance with V=100/p3 ft3 where P in psi. Eavaluate the

work done on or by the substance as the pressure increases from 10 psia to 100 psia.

Answer 1

$$W=\int_{V_1}^{V_2}pdV$$

$$W=\int_{p_1}^{p_2}p(-50/p^2)dp=-50\ln \frac{p_2}{p_1}$$

$$=-50\ln \frac{100}{10}=-115\:\rm psia\cdot ft^3$$