If Michael Jordan has a vertical leap of 1.89 m, then what is his takeoff speed and his hang time (total time to move upwards to the peak and then return to the ground)?
v=2gh=6.1 ms,v=\sqrt{2gh}=6.1~\frac ms,v=2gh=6.1 sm,
t=2⋅2hg=1.24 s.t=2\cdot \sqrt{\frac{2h}g}=1.24~s.t=2⋅g2h=1.24 s.
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