The height of a cylindrical tank, containing 20 lb of gas at 70 psia and 115 Farenheit, IS TRIPLE ITS DIAMETER; the gas constant is R = 45 ft lbf/lbm R. find.
Solution:
V=mRTp,V=\frac{mRT}p,V=pmRT,
V=Sh=πd24h=πh336,V=Sh=\frac{\pi d^2}4 h=\frac{\pi h^3}{36},V=Sh=4πd2h=36πh3,
h=36mRTπp3=8.02 ft.h=\sqrt[3]{\frac{36 mRT}{\pi p}}=8.02~ft.h=3πp36mRT=8.02 ft.
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