Question

Two thermometers in degrees Celsius and degrees Fahrenheit are both immersed in a fluid. If the reading in degrees Fahrenheit is thrice that of the degrees Celsius reading, what is the equivalent reading in degrees Rankine?

Answer 1

Solution;

The relation between T(°c) and T(F) is;

$\frac{T_c}{5}=\frac{T_F-32}{9}$

Give the reading in Fahrenheit is thrice that of degrees;

$T_F=3T_c$

Substitute into the relation equation;

$\frac{T_c}{5}=\frac{3T_c-32}{9}$

Resolve to;

$9T_c=15T_c-160$

$T_c=\frac{160}{6}=26.66°c$

The relation between Rankine and Celsius is;

$T_R=\frac95(T_c+273.15)$

By direct substitution;

$T_R=\frac95(26.66+273.15)$

$T_R=539.67°R$