Solution;
For an adiabatic nozzle;
W=0
Q=0
Given;
m˙=1360kg/h=0.3778kg/s
P1=1378kPa
v=0.147m3/kg
u1=2510kJ/kg
P2=137.8kPa
v2=1.099m3/kg
u2=2263kJ/kg
V1=3.05m/s
Energy balance equation;
h1+2000v12=h2+2000v22
But h=u+PV
u1+P1v1+2000V12=u2+P1v1+2000V22
By direct substitution;
2510+1378×0.147+20003.052=2263+137.8×1.099+2000V22
V22=621409.3025
V2=788.3m/s
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