Question #249636

A car is designed to get its energy from a rotating flywheel in the shape of a uniform, solid disk of radius 0.650 m and mass 600 kg. Before a trip, the flywheel is attached to an electric motor, which brings the flywheel's rotational speed up to 4.90  103 rev/min.


(a)

Find the kinetic energy stored in the flywheel (in J).

 __J


(b)

If the flywheel is to supply energy to the car as a 11.0 hp motor would, find the length of time in hours the car could run before the flywheel would have to be brought back up to speed.

__ h



1
Expert's answer
2021-10-17T16:54:34-0400

Solution;

Given;

Radius,R=0.65m

Mass,M=600kg

Rotation,N=4.90×103RPM

(a)

Kinetic energy is given by;

K.E=12×I×w2\frac12×I×w^2

II is the moment of inertia given by;

I=12mR2I=\frac12mR^2

I=12×600×0.652I=\frac12×600×0.65^2

I=126.75kgm2I=126.75kgm^2

The angular velocity,w;

w=2πN60w=\frac{2πN}{60} =2×π×4.90×10360\frac{2×π×4.90×10^3}{60}

w=513.126rad/sw=513.126rad/s

Kinetic energy ;

K.E=12×I×w2K.E=\frac 12×I×w^2

K.E=0.5×126.75×(513.126)2K.E=0.5×126.75×(513.126)^2

K.E=16686529.25JK.E=16686529.25J

(b)

11hp=8202.7W

t=16686529.258202.7=2034.27st=\frac{16686529.25}{8202.7}=2034.27s

Convert into hours;

t=2034.273600=0.565hrst=\frac{2034.27}{3600}=0.565hrs

t=0.565 hours







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