A wire has a length of 1.20m, a diametee 0.64mm
amd a resistance of 2.4ohms.
calculate the resistance of a wire of the same material of length 0.80 metre and diametre 0.32mm
Given:
l1=1.20 ml_1=1.20\:\rm ml1=1.20m
d1=0.64 mm=6.4∗10−5 md_1=0.64\:\rm mm=6.4*10^{-5}\:\rm md1=0.64mm=6.4∗10−5m
l2=0.80 ml_2=0.80\:\rm ml2=0.80m
d1=0.32 mm=3.2∗10−5 m=d1/2d_1=0.32\:{\rm mm}=3.2*10^{-5}\:{\rm m}=d_1/2d1=0.32mm=3.2∗10−5m=d1/2
R1=2.4 ΩR_1=2.4\:\OmegaR1=2.4Ω
The resistance of a wire is given by
Hence
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