(a) The maximum height is
"h=\\frac{(v\\sin\\theta)^2}{2g}=3.25\\text{ m}," the maximum distance is
"R=\\frac{v^2\\sin(2\\theta)}{g}=9.8\\text{ m}." The hangtime is
"T=\\frac{2v\\sin\\theta}g=1.63\\text{ s}." 1. The range of the arrow is
"R=\\frac{10^2\\sin50\u00b0}{9.8}=7.82\\text{ m}."
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