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Question #248903
John kicks the ball, and the ball does a projectile motion with an angle of 53o to horizontal with an initial velocity of 10 m/s. What is (a) its maximum height, (b) its maximum distance, and (c) its hangtime?
Find the range of an arrow that leaves the box at 50 m/s at ang angle of 50o above the horizontal?
Expert's answer
(a) The maximum height is
h
=
(
v
sin
θ
)
2
2
g
=
3.25
m
,
h=\frac{(v\sin\theta)^2}{2g}=3.25\text{ m},
h
=
2
g
(
v
sin
θ
)
2
=
3.25
m
,
the maximum distance is
R
=
v
2
sin
(
2
θ
)
g
=
9.8
m
.
R=\frac{v^2\sin(2\theta)}{g}=9.8\text{ m}.
R
=
g
v
2
sin
(
2
θ
)
=
9.8
m
.
The hangtime is
T
=
2
v
sin
θ
g
=
1.63
s
.
T=\frac{2v\sin\theta}g=1.63\text{ s}.
T
=
g
2
v
sin
θ
=
1.63
s
.
1. The range of the arrow is
R
=
1
0
2
sin
50
°
9.8
=
7.82
m
.
R=\frac{10^2\sin50°}{9.8}=7.82\text{ m}.
R
=
9.8
1
0
2
sin
50°
=
7.82
m
.
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on Jan 2024
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