1)
∇ × A ⃗ = 0 ⃗ , \nabla ×\vec A=\vec 0, ∇ × A = 0 ,
∇ × A ⃗ = ( ∂ A z ∂ y − ∂ A y ∂ z ) i ⃗ + ( ∂ A x ∂ z − ∂ A z ∂ x ) j ⃗ + ( ∂ A y ∂ x − ∂ A x ∂ y ) k ⃗ = ( − 1 + 1 ) i ⃗ + ( 4 − 4 ) j ⃗ + ( 2 − 2 ) k ⃗ = 0 ⃗ , \nabla×\vec A=(\frac{\partial A_z}{\partial y}-\frac{\partial A_y}{\partial z})\vec i+(\frac{\partial A_x}{\partial z}-\frac{\partial A_z}{\partial x})\vec j+(\frac{\partial A_y}{\partial x}-\frac{\partial A_x}{\partial y})\vec k=(-1+1)\vec i+(4-4)\vec j+(2-2)\vec k=\vec 0, ∇ × A = ( ∂ y ∂ A z − ∂ z ∂ A y ) i + ( ∂ z ∂ A x − ∂ x ∂ A z ) j + ( ∂ x ∂ A y − ∂ y ∂ A x ) k = ( − 1 + 1 ) i + ( 4 − 4 ) j + ( 2 − 2 ) k = 0 ,
2)
∇ φ = ∂ A ∂ x i ⃗ + ∂ A ∂ y j ⃗ + ∂ A ∂ z k ⃗ = i ⃗ − 3 j ⃗ + 2 k ⃗ . \nabla \varphi=\frac{\partial A}{\partial x}\vec i+\frac{\partial A}{\partial y}\vec j+\frac{\partial A}{\partial z}\vec k=\vec i-3\vec j+2\vec k. ∇ φ = ∂ x ∂ A i + ∂ y ∂ A j + ∂ z ∂ A k = i − 3 j + 2 k .