Answer to Question #194166 in Molecular Physics | Thermodynamics for Mukesh Dhami

Question

A solid of mass 200g is heated to a temperature of 80 degree Celsius and is found to melt just 40g of ice. Specific latent heat of ice = 3.36*10^6 J kg-1 K-1 , calculate specific heat capacity of solid.

Answer 1

S=specific heat capacity

M=melted mass

m=initial mass

L=latent heat

$mS(ΔT)=ML$

$0.2kgS(353K-273K)=.04kg×3.36×10^6Jkg^{-1}$

S=$0.134×10^6$ K kg^-1k^-1